PHP program to check leap year:
The below program is to check if the given year is a leap year or not. The PHP echo statement is used to output the result on the screen. A normal year is of 365 days. A year with 366 days is called a leap year. After every four years, there is a leap year.
Leap Year Conditions:
Remainder (Year/ 4) = 0 => Remainder (Year/ 100) != 0 “OR” Remainder (Year/ 400) = 0.
Example: 2020, 2024, 2028, etc.
Example
<!DOCTYPE html> <html> <body> <?php $year = 2032; if((0 == $year % 4) & (0 != $year % 100) | (0 == $year % 400)) { echo "$year is a Leap Year."; } else { echo "$year is not a Leap Year."; } ?> </body> </html> |
Output
2032 is a Leap Year. |
