SQLite Julianday Function To convert a date as a Julian Day the SQLite Julianday function is used. The resultant is thus a floating-point number. A Julian Day can be simply understood as the number of days since November 24, 4714 BC 12:00 pm Greenwich time in the Gregorian calendar.
Syntax:
julianday(timestring [, modifier1, modifier2, ... modifier_n ] )
Example 1:
SELECT julianday('now'); |
Output:
2458700.5 |
Explanation: In the above example, we are retrieving the current date.
Example 2:
SELECT julianday('now', 'start of month'); |
Output:
2458696.5 |
Explanation: In the above example, we are retrieving the first day of the month.
Example 3:
SELECT julianday('2019-08-05', 'start of month'); |
Output:
2458696.5 |
Explanation: In the above example, we are retrieving the first day of the month.
Example 4:
SELECT julianday('now', 'start of month','+1 month', '-1 day'); |
Output:
2458726.5 |
Explanation: In the above example, we are retrieving the last day of the month.
Example 5:
SELECT julianday('2019-08-05', 'start of month','+1 month', '-1 day'); |
Output:
2458726.5 |
Explanation: In the above example, we are retrieving the last day of the month.
Example 6:
SELECT julianday('now','+2 years'); |
Output:
2459431.5 |
Explanation: In the above example, we are adding 2 years to the current date.
Example 7:
SELECT julianday('2019-08-05','+2 years'); |
Output:
2459431.5 |
Explanation: In the above example, we are adding 2 years to the specified date.
Example 8:
SELECT julianday('now','+2 days'); |
Output:
2458702.5 |
Explanation: In the above example, we are adding 2 days to the current date.
Example 9:
SELECT julianday('2019-08-05','+2 days'); |
Output: 2458702.5
Explanation: In the above example, we are adding 2 days to the specified date.
Example 10:
SELECT julianday('2019-08-05','-2 days'); |
Output:
2458698.5 |
Explanation: In the above example, we are subtracting 2 days from the specified date.
